Y=3x^2-12x+23

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Solution for Y=3x^2-12x+23 equation: 



=3Y^2-12Y+23

We move all terms to the left:

-(3Y^2-12Y+23)=0

We get rid of parentheses

-3Y^2+12Y-23=0

a = -3; b = 12; c = -23;
Δ = b2-4ac
Δ = 122-4·(-3)·(-23)
Δ = -132
Delta is less than zero, so there is no solution for the equation

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